My bad dumb *** question of the day do we just replace the word color with the color we are supposed to post in?
yes.
how many logs does each tree get us
1
huh
and if you say 50 logs, we chop down 50 logs, 1 at a time
wait so we chop down a tree and place 1 log?
No. You chop the trees individually; When you place you just put the whole number ... You dont place the trees one by one. you only chop one by one
So it'd be like:
[Ceej3] runs to the [tree]
[Ceej3] chops down [tree][1]
[Ceej3] places [1] logs in pile.
Like that?
So if was Log50.
Youd chop 50 times.
but when you do the places command it would be:
[Name] places [50] logs in the pile.
So you only chop one by one. You dont have to do the last command 50 times as well
So it'd be like: [Ceej3] runs to the [tree] [Ceej3] chops down [tree][1] [Ceej3] places [1] logs in pile. Like that?
but then dont you have to ship down another tree for a new log?
Yessir.
It's what Don said, say its 50. Do the first command once, the second command 50 times and the third command once.
If the thing is Log2
we would post
[KlounV3] runs to the [tree]
[KlounV3] chops down tree [1]
[KlounV3] chops down tree [2]
[KlounV3] places [2] logs in the pile.
So that would be 100 posts...
Whew chile the ghetto.
okay i got it
yeah I was going to maybe to try and do this but I’d need my laptop to have the slightest shot of winning so
one action per post i assume?
good luck guys!!
you were supposed to win and join our club :/
no
good luck guys!! you were supposed to win and join our club :/
If the thing is Log2 we would post [KlounV3] runs to the [tree] [KlounV3] chops down tree [1] [KlounV3] chops down tree [2] [KlounV3] places [2] logs in the pile.
You got it dude
same dskjsth
[JustQR] chops down [tree #1]
testing
If the thing is Log2 we would post [KlounV3] runs to the [tree] [KlounV3] chops down tree [1] [KlounV3] chops down tree [2] [KlounV3] places [2] logs in the pile. You got it dude
i know I’m explaining to ur friends lmaoo
Welp if you ready say ready. Im sending the first log at 9:21
Ready
I think everyone should let me win.
ready (to get flung)
Log10
yes.
how many logs does each tree get us
1
huh
and if you say 50 logs, we chop down 50 logs, 1 at a time
No. You chop the trees individually; When you place you just put the whole number ... You dont place the trees one by one. you only chop one by one
So it'd be like:
[Ceej3] runs to the [tree]
[Ceej3] chops down [tree][1]
[Ceej3] places [1] logs in pile.
Like that?
So if was Log50.
Youd chop 50 times.
but when you do the places command it would be:
[Name] places [50] logs in the pile.
So you only chop one by one. You dont have to do the last command 50 times as well
but then dont you have to ship down another tree for a new log?
Yessir.
It's what Don said, say its 50. Do the first command once, the second command 50 times and the third command once.
If the thing is Log2
we would post
[KlounV3] runs to the [tree]
[KlounV3] chops down tree [1]
[KlounV3] chops down tree [2]
[KlounV3] places [2] logs in the pile.
So that would be 100 posts...
Whew chile the ghetto.
okay i got it
yeah I was going to maybe to try and do this but I’d need my laptop to have the slightest shot of winning so
one action per post i assume?
good luck guys!!
you were supposed to win and join our club :/
no
You got it dude
same dskjsth
[JustQR] chops down [tree #1]
testing
i know I’m explaining to ur friends lmaoo
Welp if you ready say ready. Im sending the first log at 9:21
Ready
I think everyone should let me win.
ready
(to get flung)Log10
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